Question
A person has to cover a fixed distance between his home
and office. i) If he walks at 5 km/h, he reaches the office 30 minutes late. ii) If he walks at 8 km/h, he reaches the office 15 minutes early. What is the distance between his home and office?Solution
ATQ, Let distance = D km Let scheduled time to reach office = T hours Case 1: Speed = 5 km/h, 30 minutes late (30 min = 1/2 hr) D / 5 = T + 1/2 ...(1) Case 2: Speed = 8 km/h, 15 minutes early (15 min = 1/4 hr) D / 8 = T β 1/4 ...(2) Subtract (2) from (1): D/5 β D/8 = (T + 1/2) β (T β 1/4) D(1/5 β 1/8) = 1/2 + 1/4 = 3/4 1/5 β 1/8 = (8 β 5)/40 = 3/40 So: D Γ (3/40) = 3/4 D = (3/4) Γ (40/3) = 40/4 = 10 km
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