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ATQ,
Sum of the distance travelled by both runners = 600 km
Let the speed of runner B = ‘x’ km/h
So, speed of runner A = ‘x + 8’ km/h
So, 4x + 4(x + 8) = 600
Or, 4x + 4x + 32 = 600
Or, 8x = 568
Or, x = 71
So, the speed of runner A = (x + 8) = (71 + 8) = 79 km/h
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