Question
If a car runs at 30 km/hr, it reaches its destination
late by 15 minutes but if runs at 45 km/hr it is late by 7 minutes. What is the correct time for the journey?Solution
Distance = Difference in time x (S1 x S2)/(S1 – S2) D = [15 – 7]/60 x {(30 x 45)/[45 – 30]} => (8/60) x (30 x 45)/15 => 12 km Time, T = D/S (take any one of the speed) => 12/30 = 12/30 x 60 = 24 minutes Then, correct time is 24 – 15 = 9 minutes
More Time and distance Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? = 41.92% of 49.96% of (45.07 1.97 – 4.98 2.03 )
(15.15 ×  31.98) + 30.15% of 719.99 = ? + 124.34
15.2 x 1.5 + 258.88+ ? = 398.12 + 15.9
784.69 + 86.96 ÷ 29.01 = 40.01 + ? + 367.88
(29.892 × √290) + 32.98 × 6.91 = ?
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
 (3/5) of 3025 + (18² + 12²) = ? + 22.22% of 1125
24.75% of 20.125% of 30.05% of 2196.06 = ?Â
(799.81/64) ÷ (10/799.92) × (129.84/130) = ?
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