Question
A can complete a piece of work in 12 days, and B can
complete the same work in 16 days. They work together for 4 days, and then A leaves. How many more days will B take to finish the remaining work?Solution
Work done by A in 1 day = 1/12, Work done by B in 1 day = 1/16 Work done by A and B together in 1 day = (1/12) + (1/16) Taking LCM of 12 and 16 = 48, Work done together = (4/48) + (3/48) = 7/48 Work done in 4 days = 4 × (7/48) = 28/48 = 7/12 Remaining work = 1 - 7/12 = 5/12 B's work rate = 1/16 Time taken by B = (5/12) ÷ (1/16) = (5/12) × 16 = 20/3 = 6.67 days. Correct Option: c) 6.67 days
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