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Let car covers 'D' km with 'v' km/h in 'T' hours. Using, distance = speed X time We have, 'D' = vT ----- (I) ATQ: We have, (v + 20) X (T - 2) = 'D' ---------- (II) And, (v - 10) X (T + 1.6) = 'D' ----- (III) (1 hour 36 minutes = (96/60) = 1.6 hours) Using equation (II) and (III) , We have, (v + 20) X (T - 2) = (v - 10) X (T + 1.6) Or, vT - 2v + 20T - 40 = vT + 1.6v - 10T - 16 Or, 3.6v - 30T + 24 = 0 Or, 6v - 50T + 40 = 0 --------- (IV) Using equation (I) and (II) , We have, (v + 20) X (T - 2) = vT Or, vT - 2v + 20T - 40 = vT Or, v - 10T + 20 = 0 ------ (V) On solving equation (IV) - 6 X equation (V) , We have, (6v - 50T + 40) - 6 X (v - 10T + 20) = 0 Or, 6v - 50T + 40 - 6v + 60T - 120 = 0 Or, 10T = 80 Or, 'T' = 8 hours
3 2 10 ? 17 16
15.975 ×27.825 + (76.01)² + 12.98×18.426 = ?+ (79.09)²
120, 136, 111, 147, ?, 162
80, ?, 240, 80, 20, 4
12 18 31 51 ? 112
3, 8, 27, 124, ?
362 452 550 656 770 892 ?
...76, 80, 89, 105, ?, 166
24, 8, 15, ?, 12, 4
What will come in place of the question mark (?) in the following series?
7, 20, 59, 176, 527, 1580, ?