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Let car covers 'D' km with 'v' km/h in 'T' hours. Using, distance = speed X time We have, 'D' = vT ----- (I) ATQ: We have, (v + 20) X (T - 2) = 'D' ---------- (II) And, (v - 10) X (T + 1.6) = 'D' ----- (III) (1 hour 36 minutes = (96/60) = 1.6 hours) Using equation (II) and (III) , We have, (v + 20) X (T - 2) = (v - 10) X (T + 1.6) Or, vT - 2v + 20T - 40 = vT + 1.6v - 10T - 16 Or, 3.6v - 30T + 24 = 0 Or, 6v - 50T + 40 = 0 --------- (IV) Using equation (I) and (II) , We have, (v + 20) X (T - 2) = vT Or, vT - 2v + 20T - 40 = vT Or, v - 10T + 20 = 0 ------ (V) On solving equation (IV) - 6 X equation (V) , We have, (6v - 50T + 40) - 6 X (v - 10T + 20) = 0 Or, 6v - 50T + 40 - 6v + 60T - 120 = 0 Or, 10T = 80 Or, 'T' = 8 hours
Find the odd one out.
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If Geeta walks 15 km towards West, then turned towards South and walked 15 km, then turned East walked 15 km, and turned North walked 15 km. How far she...
Study the following information carefully and answer the given questions:
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Statement:
P < M ≤ Y = X; U > A =C; P < C = O > E
Conclusions:
I). Y > C
II). X < E
...If C is 4m to the south of Q, then find the distance between V and C?