Question
A car moves from city ‘A’ to city ‘B’ at 50 km/h
and returns back from city ‘B’ to city ‘A’ at 75 km/h. Find the car’s average speed during the entire round trip.Solution
ATQ,
Let the distance between city ‘A’ and ‘B’ = D km
Average speed = Total distance / Total time
Average speed = (D + D) / [(D / 50) + (D / 75)]
= 2D / [(3D + 2D)/150]
= 2D / (5D / 150)
= (2D / 5D) × 150
= 60 km/h
More Time and distance Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
5999.93 ÷ 60.005 × 70.002 = ? × 24.9
(1560.23 ÷ 25.98) + (768.32 ÷ 23.9) + 1814.11 = ?
40.22 of 249.98% + 459.99 ÷ 23.18 = ?
159.98% of 4820 + 90.33% of 2840 = ? + 114.99% of 1980
1587.9 + 9650.98 + 10612.8 =?3 - 2536.67
7.992 + (4.01 × 3.98) + ? = 224.03
(5.013 – 30.04) = ? + 11.98% of 4799.98
7.9% of 174.92 + 24.99 - 131.99 ÷ 11.95 × 2.98 = ?
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