Question
Priya needs to travel from town 'X' to town 'Y'. If she
drives at a steady speed of 60 km/h, she arrives 36 minutes early. However, if she drives at 40 km/h, she arrives 45 minutes late. What is the distance between town 'X' and town 'Y'?Solution
ATQ,
Let the distance between towns 'X' and 'Y' be 'd' km
Let the correct time to travel be 't' hours
According to the question,
(d/40) = t + (45/60) = t + 0.75
And, (d/60) = t - (36/60) = t - 0.6
Or, (d/40) - (d/60) = t + 0.75 - (t - 0.6)
Or, (3d - 2d) ÷ 120 = 1.35
Or, d/120 = 1.35
Or, d = 1.35 × 120 = 162
Therefore, the distance between town 'X' and 'Y' is 162 km.
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
9 × 40 × 242 × 182 = ?2
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
52% of 400 + √(?) = 60% of 600 - 25% of 400
447.8 × 441.2 ÷ 445 = 44 × 44?
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7What will come in the place of question mark (?) in the given expression?
(? ÷ 16) = (20 ÷ ?) X 20- What will come in the place of question mark (?) in the given expression?
62.5% of 120 + ? = (720 + 90) ÷ √36 - What will come in place of the question mark (?) in the following questions?
25% of 360+40=? 30% of 2200 +’?’ x 50 – 1020 = 11x 306 + (√ 2250 ÷ 0.1) Â
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