Question
Priya needs to travel from town 'X' to town 'Y'. If she
drives at a steady speed of 60 km/h, she arrives 36 minutes early. However, if she drives at 40 km/h, she arrives 45 minutes late. What is the distance between town 'X' and town 'Y'?Solution
ATQ,
Let the distance between towns 'X' and 'Y' be 'd' km
Let the correct time to travel be 't' hours
According to the question,
(d/40) = t + (45/60) = t + 0.75
And, (d/60) = t - (36/60) = t - 0.6
Or, (d/40) - (d/60) = t + 0.75 - (t - 0.6)
Or, (3d - 2d) ÷ 120 = 1.35
Or, d/120 = 1.35
Or, d = 1.35 × 120 = 162
Therefore, the distance between town 'X' and 'Y' is 162 km.
I. 15y2 + 4y – 4 = 0
II. 15x2 + x – 6 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I. x3 = 1728
II. y2 – 15y + 56 = 0
I. 40x² + 81x + 35 = 0
II. 63y² + 103y + 42 = 0
I. 35x² - 51x + 18 = 0
II. 30y² + 17y – 21 = 0
I. 2y² - 35y + 132 = 0
II. 2x² - 31x + 110 = 0
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. p²= ∛1331
II. 2q² - 21q + 55 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
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