Question
A Policeman spotted a thief 30 meters ahead of him. The
moment they both saw each other they started running in the same direction on the same track. The thief was running at 9m/sec and the policeman was chasing him at the speed of 12 m/sec. How much distance the policeman needs to cover to catch the thief.? ÂSolution
Relative speed = 12 m/sec - 9 m/sec = 3 m/sec  Time to close the gap = 30 meter /3 m/sec = 10 seconds Distance covered by the policeman: 12 m/sec × 10 seconds = 120 meters The distance the policeman needs to cover = 120 meters.
Given below are two numbers series 'I' and 'II' and each series has a wrong (odd one out) number. The number that should come in place of the wrong num...
1331      1000            729       512       ?             216
...7Â Â Â Â Â Â Â Â Â Â Â 26Â Â Â Â Â Â Â Â Â Â Â Â Â Â 238Â Â Â Â Â Â Â Â Â Â Â Â Â Â 962Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 8522Â Â Â Â Â Â Â Â Â Â Â Â Â ...
Direction: Which of the following will replace ‘?’ in the given question?
342, ‘?’, 420, 462, 506, 552, 60
7 12 33 ? 635 3804
...If 6 4 x 5.75 9,
Then, (x²-1) = ?
...6Â Â Â Â Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â Â Â Â Â 15Â Â Â Â Â Â Â Â Â Â 46Â Â Â Â Â Â Â Â Â Â 185Â Â Â Â Â Â Â Â ?
...Identify the given logic and complete the series with the correct option. 12, 15, 18, 20,?
(45)2 ÷ ∛729 + (35)2 ÷ 1.4 =?
2187, 1458, 972, ?, 432, 288
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