Question
Two cyclists are riding towards one another at speeds of
36 km/h and 27 km/h. What will be the distance between them 5 seconds before they meet?Solution
ATQ,
Relative speed of one cyclist with respect to the other = 36 + 27 = 63 km/h = 63 á 3.6 = 17.5 m/s
So, distance between them 5 seconds before meeting = 17.5 Ă 5 = 87.5 metres
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