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    Question

    Two cyclists are riding towards one another at speeds of

    36 km/h and 27 km/h. What will be the distance between them 5 seconds before they meet?
    A 55.5 m Correct Answer Incorrect Answer
    B 75 .5 m Correct Answer Incorrect Answer
    C 87.5 m Correct Answer Incorrect Answer
    D 62.5 m Correct Answer Incorrect Answer

    Solution

    ATQ,

    Relative speed of one cyclist with respect to the other = 36 + 27 = 63 km/h = 63 ÷ 3.6 = 17.5 m/s

    So, distance between them 5 seconds before meeting = 17.5 × 5 = 87.5 metres

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