A person travels from the hostel to the college at a speed of 10 kmph on the bicycle and reaches a 4.5-minute delay. If he runs a bike with a speed of 20 kmph, then it reaches 4.5 minutes. Describe the distance between the hostel and the college. (In km)
Let us consider the time of the journey be t hrs, As we know, the distance is the same. According to the question 10 (t + 4.5/60) = 20 (t-4.5/60) 2 (t + 3/40) = 4 (t-3/40) 2t+ 3/20 = 4t-12/40 4t-2t = 3/20 + 12/40 2 t = 18/40 t=9/40 Distance = speed × time Distance = 10 (9/40 + 3/40) = 3 km
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