New RBI Grade B 2025 Notification will come Soon! Enroll Here

    Question

    In a Drag race of 'm' metres, 'Amit' beats 'Binod' by

    'a' metres and 'Binod' beats 'Chintu' by 'b' metres. By how much distance (in metres) will 'Amit' beat 'Chintu', in the same race?
    A [(a + b) - (ab/m)] Correct Answer Incorrect Answer
    B [(a - b) - (ab/m)] Correct Answer Incorrect Answer
    C [(a + b) + (ab/m)] Correct Answer Incorrect Answer
    D [(a - b) + (ab/m)] Correct Answer Incorrect Answer
    E [(a × b) - (ab/m)] Correct Answer Incorrect Answer

    Solution

    ATQ, we can say that Ratio of speeds of 'Amit' and 'Binod' is = m:(m - a) Ratio of speeds of 'Binod' and 'Chintu' = m:(m - b) So, ratio of speeds of 'Amit' and 'Chintu' = m2:(m - b) × (m - a) = m2: (m2- ma - mb + ab) So, distance covered by 'Chintu' in the time taken by 'Amit' to cover 'm' metres is = m - {m - (a +b) + (ab/m)} = [(a + b) - (ab/m)] 

    Practice Next

    Relevant for Exams: