Question
In a 500-metre race, βAβ beats βBβ by 15 seconds
or 75 metres. Find the time taken by βBβ to finish the race.Solution
Speed of βBβ = (75/15) = 5 m/s Time taken by βBβ to finish the race = 500 Γ· 5 = 100 seconds
More Time and distance Questions
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(9/20 of 3998.93) - β2499.57 + (17.87% of 1199.67) = ?
Find the approximate value of Question mark(?) for given equation.Β
104.85% of 479.89 β β2400.91 + (71.92 Γ· 6.03) Γ 24.85 = ?
...41.78% of 1499 + (9/13) Γ 389.84 = ?% of 1599.67 + 180.45
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
15.08% of (133.13 + 146.928) + 8.033 - (8.98 of 6.01) = ? of (46.09 - 20.98)
?2 + (39.99 Γ 10.99 + 7.01) - (39.99 Γ 2.992 + 21.99) = 21.99 Γ 23.01
(33.95)2 – (25.004)2 + (18.0099)2 – (9.07)2 = ? - (14.990)2
1240.04 β 360.18 + 449.98 Γ· 15.06 = ?
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