Let distance be x km and speed be y km/hr x/(y - 20) - (x/y) = 80 x = 4y(y - 20) .............(1) (x/y) - x/(y + 10) = 20 x = 2y(y + 10) ..............(2) From (1) and (2), we get 4y(y - 20) = 2y(y + 10) 2y - 40 = y + 10 y = 50 km/hr Then x =2 × 50 (50 + 10) = 100 × 60 = 6000 km
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Find the distance travelled (in km) by the truck to reach point B from point A, if a car cover 25% the same distance in 2 hours and a truck covers 30%...