Question
A man is travelling at a speed of 30 km/h such that he
will take 70 minutes to reach his destination. But after completing half the journey, the man took a break of 25 minutes and then continued his journey. Find the speed at which the man must cover rest of the journey to reach his destination in original time.Solution
Total distance to be covered = 30 × (70/60) = 35 km Time taken to cover half the distance at original speed = {(35 ÷ 2) ÷ 30} × 60 = 35 minutes Time remaining = 70 – 35 – 25 = 10 minutes Required speed = 17.5 ÷ 10 × 60 = 105 km/h
The radius of the incircle of a triangle is 3 cm. if the area of the triangle is 12 cm 2 , then its perimeter is?
The internal bisector of ∆ABC at ∠A cuts BC on D and cuts the circumcircle at E. If DE = 6cm, AC = 8cm and AD = 10 cm, then find the length of AB?
The length of the each side of an equilateral triangle is 7√3 cm . The area of circumcircle, (cm 2 ) is
In a regular polygon, the ratio of the exterior angle to the interior angle is 4:5. Find the interior angle of the polygon.
Find area of a sector of radius 14 cm with central angle 90°. (π = 22/7)
What will be inradius of an equilateral triangle of side 10 cm?
In a circle, two chords of lengths p and q subtend the angles of 60° and 90° at the center respectively. Which of the following is correct in this sce...
If O is circumcentre of acute angled triangle ABC, if ∠ BAC = 70˚ then ∠BOC = ?
In ΔABC, PQ is parallel to BC If AP: PB= 2:5 and AQ= 2 cm, AC is equal to?
