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Distance covered in a day = 28 × 5 = 140 km Days required to cover distance = 2000 ÷ 140 = 14.28 days Thus, he will reach the destination only on the 15th day. He will travel for 4 days in the first week, 6 days in the second , 4 days in the third week to reach his destination on Friday.
? 2 – 17.89 2 + 15.33% of 1199.76 = 49.54% of 49.68
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
1456.92 + ? – 1324.87 = 1875.34 – 1683.29
766/51 ÷ 387/42 × 121/13 = ?
15.22 × 9.99 + 150.15 = ?
(2160.23 ÷ 35.98) + (600.32 ÷ 23.9) + 1744.11 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
32.052- 22.03 x 24.199 - 15.18 x 11.04 = ?
