Question
Two person A and B started from same place and in same
direction with speed of 48km/hr and 40km/hr respectively .The speed of person B increased by ½ km every hr. after what time A and B will meet .Solution
Let the time be =  t hrs , speed be= 48 km/hr , distance = 48× t Distance travelled by B forms an AP = 40, 40½, 41, 41½ , ………………………. t terms Where First term is 40 and Common difference is 1/2 Now, Sum of n terms = Sn = n/2 [2a + (n-1)d] = distance covered by A Sn = t/2 [2 × 40 + (t-1) 1/2] 48t= t/2 [2 × 40 + (t-1) 1/2] 96 = 80 + (t – 1) 1/2 16 = (t – 1) 1/2 33 = t Therefore A and B will meet after 33 hours
Demographic transition theory of population was proposed by
When one buyer and larger number of sellers, the market condition is known as
viroid consists of
The loan criteria for Kisan credit card scheme includes:
What is the maximum limit of chemically untreated conventionally grown raw material that can be used for making compost in an organic mushroom productio...
Which nutrient helps in preventing Microcytic Anaemia?
What is the cause of the "Little leaf" disorder in cotton?
Method of extreme form of minimum tillage where primary tillage is completely avoided and secondary tillage is restricted to row zone or seed bed zone o...
The element is found highest in earth crust is:
The action to remove food from the market at any stage of the food chain, including that possessed by consumers is called:
Relevant for Exams:
