Question
if 3P=9q=27t and 1/3P+1/6q+1/9t=36/7 , then t =
?Solution
3P=9q=27t =x P=x/3 q=x/9 t=x/27 now-  1/3P+1/6q+1/9t=36/7 Put the value of p,q, and t. 1/k+3/2k+3/k =36/7 (6+3)/2k=36/7 k=63/72=7/8 k=7/8. Then – t=k/27 =7/8×27 =7/216. Â
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