Question
1800 metres long train crosses a man who is moving in
the same direction with a certain speed, in 18 seconds. If the same train can cross a tree in 9 seconds with the same speed, then find the speed of the man.Solution
Speed of train = 1800/9 = 200 m/sec Let the speed of the man be ‘s’ m/sec Relative speed of the train = (200 – s) m/sec According to the question, (200 – s) = 1800/18 Or, s = 200 – 100 = 100 Therefore, speed of the man = 100 m/sec
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3 × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2
15% of 1800 + 22 = ?
