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x²y² + (1/ (x2y2)) = 83 By subtracting 2 from both sides, we get ⇒ x²y² + (1/ (x2y2)) - 2 = 83 - 2 ⇒ (xy - 1/xy)2 = 81 ⇒ (xy - 1/xy) = √81 ∴ (xy - 1/xy) = 9
If the ratio of the area of two similar triangles is √3:√2 then what is the ratio of the corresponding sides of the two triangles?
The inner-radius of a triangle is 5 cm, and the sum of lengths of its sides is 60 cm. What is the area of the triangle (in sq. cm.)?
What is the height of an equilateral triangle with a side length of 8√3 cm?
In triangle ABC, the difference between angle A and angle B is 16°, and the difference between angle A and angle C is 8°. Determine the measure of an...
Find the area of a triangle whose sides are 12 m, 14 m, and 16 m.
If the side of an equilateral triangle is 12cm, then find the area (in cm 2 ) of the triangle (correct to two decimal places).
The area of an isosceles triangle ABC is 8√5 cm 2 . If AB = BC and AC = 8 cm, then find the perimeter of triangle ABC.
If in triangle ABC, If side AB=6√ 3, AC=12 and BC=6, then angle B equals:
A △ ABC has sides 5 cm, 6 cm and 7 cm. AB extended touches a circle at P and AC extended touches the same circle at Q. Find the length (in cm) of AQ.
