Question
I. x² + 3x – 154 = 0 II. y² + 5y – 126 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. x² + 3x – 154 = 0 x² + 14 x - 11 x – 154 = 0 x (x + 14) – 11(x + 14) = 0 x = 11, - 14 II. y² + 5y – 126 = 0 y² - 9y + 14 y – 126 = 0 y (y – 9) + 14(y – 9) = 0 y = 9, - 14 Hence, relationship cannot be established between x and y
Simplify the following expressions and choose the correct option.
{[(13)² − (7)²] ÷ 12} × 4 = ?
(25)² × 4 ÷ 5 + (3)³ + 48=? + 425
?2 + 114 - 48 ÷ 2 × 5 = 163
182 + 10 × 12 - ? = 312
2/5 of 3/4 of 7/9 of 7200 = ?
If (3 × 144 – 252 ÷ 14) ÷ 18 = √1024 – x, then find the value of ‘x’.
12.50% of 1440 - 17 × 51 + 721 =?
[(15)³ × (8)²] ÷ (90 × 6) = ?²
?2 - (40% of 240) = 25 X 5
Simplify: 48 ÷ 4 × 3 + 5 × (6 − 2)