Question
A man invested Rs. 20,000 at simple interest of 10% p.a.
If he had instead invested the same sum on compound interest of 10% p.a., compounded annually, then how much more he would have earned as interest after 2 years?Solution
ATQ, Simple interest = Sum × (rate of interest/100) × (time in years) Simple interest earned in two years = 20,000 × (10/100) × 2 = Rs. 4,000 Compound interest earned in two years: = 20,000 × {1 + (10/100)}² - 20,000 = 20,000 × (1.1)² - 20,000 = 20,000 × 1.21 - 20,000 = Rs. 24,200 - 20,000 = Rs. 4,200 So, required difference = 4,200 - 4,000 = Rs. 200
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
56 x 8 – 65% of 40 = ? + 14 x √625
240 + 25% of 420 – 145 =? + (2.5 + 8.5) 2
If 28957.5 ÷ 268.125= 108, then 289.575 ÷ 2681.25 is equal to:
? = (22% of 25% of 60% of 3000) + 21
? ÷ [35% of 379 - 34(4/5)] = 0.4
420 ÷ 7 + 140 % of 20 + ? × 13 = 18 × 15
[4(2/3) + 5(1/6)] × 45% of 240 = ?
What will come in the place of question mark (?) in the given expression?Â
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...182 – 517 ÷ 11 - √361 = ?
