Question
Simple interest earned on an amount of Rs.1200 at rate
of R% per annum after 2 years is Rs.216. Find the simple interest earned on an amount of Rs.1400 at rate of (R + 4)% per annum after 3 years.Solution
According to question, => 216 = 1200 × R% × 2 => R = 216/24 = 9 Therefore, required interest = 1400 × (9 + 4)% × 3 = Rs.546
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
For given pair of equations, how many solutions are possible?
4x + 6y = 16 and 8x + 12y = 32
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
Find the area between the lines 18x +12y = 108, 9x  + 6y  = 27, x - axis and y -axis.Â
If in two linear equations ax + by = c and dx + ey = f and a/d = b/e = c/f then, which of the following is true about the two equations?
For which value of m, there is no solution to the equation -
a – b = 5
ma – 4b = 1
The lines x + y = 9 and x - y = 3 intersect at point P. Find the coordinates of P.
Solve: (x/3) + (x/5) = 16
Find the value of 'a' and 'b' which satisfy the following equations:
9a + 7b = 30
4a - 5b = 62
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.