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      Question

      Two number series, I and II, are given below, which

      contain a missing term β€˜x’ and β€˜y’ respectively. Each series follows a different pattern. Series I: 12, 14, 31, x, 399, 2006 Series II: 19, 42, y, 264, 796, 1596 Find the relationship between β€˜x’ and β€˜y’.
      A x > y Correct Answer Incorrect Answer
      B x < y Correct Answer Incorrect Answer
      C x = y or the relationship cannot be established Correct Answer Incorrect Answer
      D x β‰₯ y Correct Answer Incorrect Answer
      E x ≀ y Correct Answer Incorrect Answer

      Solution

      Series I: Multiplication by successive numbers and addition of successive prime numbers. 12 X 1 + 2 = 14 14 X 2 + 3 = 31 31 X 3 + 5 = 98 98 X 4 + 7 = 399 399 X 5 + 11 = 2006 So, β€˜x’ = 98 Series II: Alternative multiplication by 2 and 3 followed by the addition of 4 19 X 2 + 4 = 42 42 X 3 + 4 = 130 130 X 2 + 4 = 264 264 X 3 + 4 = 796 796 X 2 + 4 = 1596 So, β€˜y’ = 130 So, x < y. Hence, option B.

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