Question
Two number series, I and II, are given below, which
contain a missing term βxβ and βyβ respectively. Each series follows a different pattern. Series I: 12, 14, 31, x, 399, 2006 Series II: 19, 42, y, 264, 796, 1596 Find the relationship between βxβ and βyβ.Solution
Series I: Multiplication by successive numbers and addition of successive prime numbers. 12 X 1 + 2 = 14 14 X 2 + 3 = 31 31 X 3 + 5 = 98 98 X 4 + 7 = 399 399 X 5 + 11 = 2006 So, βxβ = 98 Series II: Alternative multiplication by 2 and 3 followed by the addition of 4 19 X 2 + 4 = 42 42 X 3 + 4 = 130 130 X 2 + 4 = 264 264 X 3 + 4 = 796 796 X 2 + 4 = 1596 So, βyβ = 130 So, x < y. Hence, option B.
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