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      Question

      Three series (I, II and III) are given below. Each

      series contain one odd one out (wrong term) . Wrong term in series I, III and II is denoted by 'P', 'Q' and 'R' respectively. Series I: 370, 396, 435, 503, 598, 736 Series II: 279, 380, 453, 510, 579, 664 Series III: 5940, 1485, 330, 60, 12, 2 Find the sum of each term which should come in place of 'P', 'Q' and 'R'. 
      A 858 Correct Answer Incorrect Answer
      B 946 Correct Answer Incorrect Answer
      C 942 Correct Answer Incorrect Answer
      D 954 Correct Answer Incorrect Answer
      E 836 Correct Answer Incorrect Answer

      Solution

      Series I: (consecutive prime numbers X consecutive natural numbers) 374 + 11 x 2 = 396 396 + 13 x 3 = 435 435 + 17 x 4 = 503 503 + 19 x 5 = 598 598 + 23 x 6 = 736 374 should come in place of 370 So, 'P' = 370 Series II: 279 + (102 + 12) = 279 + 101 = 380 380 + (82 + 32) = 380 + 73 = 453 453 + (62 + 52) = 453 + 61 = 514 514 + (42 + 72) = 514 + 65 = 579 579 + (22 + 92) = 579 + 85 = 664 514 should come in place of 510 So, 'R' = 510 Series III: 5940 ÷ 4 = 1485 1485 ÷ 4.5 = 330 330 ÷ 5 = 66 66 ÷ 5.5 = 12 12 ÷ 6 = 2 66 should come in place of 60 So, 'Q' = 60 Required sum = 374 + 66 + 514 = 954

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