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    Question

    720 sweets are divided among four kids in the ratio

    (1/5):(1/6):5:9. The second highest recipient got how many more sweets than the lowest recipient?
    A 133 Correct Answer Incorrect Answer
    B 218 Correct Answer Incorrect Answer
    C 160 Correct Answer Incorrect Answer
    D 241 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Given Ratio = (1/5):(1/6):5:9.

    Multiplying all values by 30 i.e. LCM of 5 and 6,

    The ratio becomes = 6:5:150:270

    So, number of sweets received by the second highest recipient = 720 × (150/431) = 250

    Number of sweets received by the least recipient = 720 × (5/431) = 9

    So, required difference = 250 - 9 = 241

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