Question
'A' and 'B' have marbles in the ratio of 5:3,
respectively. If 'B' gives 4 marbles to 'A', then the new ratio of marbles with 'A' and 'B' becomes 3:1, respectively. Find the initial difference between marbles with 'A' and 'B'.Solution
Let the initial number of marbles that 'A' and 'B' have be 5x and 3x , respectively.
After giving 4 marbles to 'A', the number of marbles with 'A' and 'B' will be: (5x+4) and (3x-4)
ATQ;
{5x+4}/{3x - 4} = {3/1}
Or, 5x+4=3(3x-4)
Or, 5x + 4 = 9x – 12
Or, 4x=16
Or, x=4
The initial difference between marbles with 'A' and 'B': 5x – 3x = 2x = 8
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