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      Question

      'A' and 'B' have marbles in the ratio of 5:3,

      respectively. If 'B' gives 4 marbles to 'A', then the new ratio of marbles with 'A' and 'B' becomes 3:1, respectively. Find the initial difference between marbles with 'A' and 'B'.
      A 6 Correct Answer Incorrect Answer
      B 8 Correct Answer Incorrect Answer
      C 10 Correct Answer Incorrect Answer
      D 12 Correct Answer Incorrect Answer

      Solution

      Let the initial number of marbles that 'A' and 'B' have be 5x and 3x , respectively.
      After giving 4 marbles to 'A', the number of marbles with 'A' and 'B' will be: (5x+4) and (3x-4)
      ATQ;
      {5x+4}/{3x - 4} = {3/1}
      Or, 5x+4=3(3x-4)
      Or, 5x + 4 = 9x – 12
      Or, 4x=16
      Or, x=4
      The initial difference between marbles with 'A' and 'B': 5x – 3x = 2x = 8

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