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    Question

    'A' and 'B' have marbles in the ratio of 5:3,

    respectively. If 'B' gives 4 marbles to 'A', then the new ratio of marbles with 'A' and 'B' becomes 3:1, respectively. Find the initial difference between marbles with 'A' and 'B'.
    A 6 Correct Answer Incorrect Answer
    B 8 Correct Answer Incorrect Answer
    C 10 Correct Answer Incorrect Answer
    D 12 Correct Answer Incorrect Answer

    Solution

    Let the initial number of marbles that 'A' and 'B' have be 5x and 3x , respectively.
    After giving 4 marbles to 'A', the number of marbles with 'A' and 'B' will be: (5x+4) and (3x-4)
    ATQ;
    {5x+4}/{3x - 4} = {3/1}
    Or, 5x+4=3(3x-4)
    Or, 5x + 4 = 9x – 12
    Or, 4x=16
    Or, x=4
    The initial difference between marbles with 'A' and 'B': 5x – 3x = 2x = 8

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