Question
'A' and 'B' have chocolates in the ratio of 9:4,
respectively. If 'B' gives 5 chocolates to 'A', then the new ratio of chocolates with 'A' and 'B' becomes 7:3, respectively. Find the initial difference between chocolates with 'A' and 'B'.Solution
Let the initial number of chocolates that 'A' and 'B' have be 9x and 4x, respectively.
After giving 5 chocolates to 'A', the number of chocolates with 'A' and 'B' will be: (9x + 5) and (4x-5)
ATQ;
{9x+5}/{4x - 5} = {7/3}
Or, 3(9x + 5) = 7(4x-5)
Or, 27x+15=28x – 35
Or, x = 50
The initial difference between chocolates with 'A' and 'B': 9x - 4x = 5x = 250
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