Question
The profit earned after selling an article for Rs.1516
is the same as loss incurred after selling the article for Rs.1012. What is the cost price of the article?Solution
Let CP = Rs. x Profit = Rs. y Therefore, x + y = SP => x + y = 1516 ----- (i) When SP = Rs. 1012, the loss = Rs. y Therefore, x – y = 1012 ------- (ii) Solving both the equation, we get => 2x = 2528 => x = Rs. 1264
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠-1) has equal roots. find the value of p.
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 32x + 252 = 0
Equation 2: y² - 30y + 221 = 0
I. (4x-5)3Â +Â 1/(4x-5)3Â = 2
II. 2[(y+1/y)2- 2]- 9(y+1/y)= -14
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
I. 2x² + 15 x - 27 = 0
II. 3 y² + 25 y - 18 = 0
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. Â 2(x+2)+ 2(-x)=5
II. Â (1/(y+1)+ 1/(y+5))=(1/(y+2)+ Â 1/(y+4))
Relevant for Exams:
