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    Question

    Three numbers ‘P’, ‘Q’ and ‘R’ are such

    that ‘P’ is 25% more than ‘Q’ and ‘R’ is equal to the average of ‘P’ and ‘Q’. If the sum of these three numbers is 810, then find the smallest number among them.
    A 280 Correct Answer Incorrect Answer
    B 240 Correct Answer Incorrect Answer
    C 320 Correct Answer Incorrect Answer
    D 300 Correct Answer Incorrect Answer

    Solution

    Let the value of ‘Q’ be ‘8x’ So, value of ‘P’ = 8x + {25% of 8x} = ‘10x’ So, value of ‘R’ = (10x + 8x)/2 = 18x/2 = ‘9x’ ATQ; 10x + 8x + 9x = 810 Or, 27x = 810 Or, x = 30 So, the smallest number = ‘Q’ = 8x = 8 × 30 = 240

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