Question
Three numbers βPβ, βQβ and βRβ are such
that βPβ is 25% more than βQβ and βRβ is equal to the average of βPβ and βQβ. If the sum of these three numbers is 810, then find the smallest number among them.Solution
Let the value of βQβ be β8xβ So, value of βPβ = 8x + {25% of 8x} = β10xβ So, value of βRβ = (10x + 8x)/2 = 18x/2 = β9xβ ATQ; 10x + 8x + 9x = 810 Or, 27x = 810 Or, x = 30 So, the smallest number = βQβ = 8x = 8 Γ 30 = 240
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