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    Question

    Three numbers β€˜P’, β€˜Q’ and β€˜R’ are such

    that β€˜P’ is 25% more than β€˜Q’ and β€˜R’ is equal to the average of β€˜P’ and β€˜Q’. If the sum of these three numbers is 810, then find the smallest number among them.
    A 280 Correct Answer Incorrect Answer
    B 240 Correct Answer Incorrect Answer
    C 320 Correct Answer Incorrect Answer
    D 300 Correct Answer Incorrect Answer

    Solution

    Let the value of β€˜Q’ be β€˜8x’ So, value of β€˜P’ = 8x + {25% of 8x} = β€˜10x’ So, value of β€˜R’ = (10x + 8x)/2 = 18x/2 = β€˜9x’ ATQ; 10x + 8x + 9x = 810 Or, 27x = 810 Or, x = 30 So, the smallest number = β€˜Q’ = 8x = 8 Γ— 30 = 240

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