Question
If ‘A’, ‘B’ and ‘C’ are in proportion in the
given order while ‘A’ = 16 and ‘B’ = 32, then find the value of ‘C’.Solution
Given, A = 16
And, B = 32
Since, ‘A’, ‘B’ and ‘C’ are in proportion.
So, (A/B) = (B/C)
So, C = (32 × 32)/16 = 64
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Which of the following statement is true?
Statements:
D ≤ E > I; Q ≤ I ≤ W; F = W ≥ Y
Conclusions:
I. E > Q
II. F ≥ I
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