Question
The ratio of two numbers βAβ and βBβ is 11:7, respectively. If 9 is subtracted from each of βAβ and βBβ, then the ratio of βAβ and βBβ becomes 2:1. The sum of βAβ and βBβ is:
Solution
Let the two numbers βAβ and βBβ be β11xβ and β7xβ, respectively ATQ; (11x - 9)/(7x - 9) = 2/1 Or, 11x - 9 = 14x - 18 Or, 3x = 9 Or, x = 3 Now, sum of βAβ and βBβ = 11 Γ 3 + 7 Γ 3 = 54
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