Question
Two numbers, 'A' and 'B', are initially in the ratio of
7:9. When 8 is added to the smaller number ('A') and 24 is subtracted from the larger number ('B'), the new ratio of 'A' to 'B' becomes 23:21. Find the difference between 'A' and 'B'.Solution
Let 'A' and 'B' be '7x' and '9x', respectively ATQ; (7x + 8)/(9x - 24) = 23/21 147x + 168 = 207x - 552 720 = 60x So, x = 12 So, required difference = 9x - 7x = 2x = 12 X 2 = 24
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