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Let the weight of the pieces of diamond be 2x, 3x, 5x, 6x Total weight of diamond = 2x + 3x + 5x + 6x = 16x Price ∝ (weight)2 => Price = k(weight)2 ; where, K is constant Original price = k(16x)2 Price of pieces = (4kx2 + 9kx2 + 25kx2 + 36kx2) = 74kx2 Loss in price = 256kx2 – 74kx2 = 182kx2 which is given as 91,000 => 182kx2 = 91000 => kx2 = 500 Original price = 256kx2 = 256 x 500 = 128000
Suit against a trustee of a temple for account of trust property and proceeds thereof-
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