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Let actual marks scored by A and B be 13x and 5x respectively. Difference between the marks scored by A and B = 13x – 5x = 8x According to question, => (5x + 5) × 1.3 = 13x => 6.5x + 6.5 = 13x => 6.5x = 6.5 => x = 1 Required difference = 8x = 8
if 8 sin 2 x + 3 cos 2 x = 4 then find tan x
Take θ = 450
If (1+sinθ)/cosθ = x, then find the value of secθ?
1. If cos2B = sin(1.5B - 36 o ) , then find the measure of 'B'.
If cot8A = tan(A+8˚), find the value of A? Given that 8A and A+8 are acute angles.
If 9 sinx + 40 cosx = 41 then find tanx.
sin2 9 ° + sin2 10 ° + sin2 11 ° + sin2 12 ° + ……… + sin2 81 ° = ?
...What is the value of cos [(180 – θ)/2] cos [(180 – 9θ)/2] + sin [(180 – 3θ)/2] sin [(180 – 13θ)/2]?