Question
If A varies directly as B and inversely as C and A = 8,
B = 2 and C = 5, what is the value of A when B = 6 and C = 5?Solution
Let the constant be x, According to the question, => A = x × B/C => 8 = x × 2/5 => x = 20 Now putting the value of A, => A = 20 × (6/5) => A = 24
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