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Let annual salary of P, Q and R two years ago be 4x, 3x and 5x respectively. Present salary of P = Rs. 19,360 (given) ∴ 4x× 110/100×110/100 × 1/12 = 19,360 ⟹ 121x/300 = 19360 ∴ x = (19360 × 300)/121 ∴ x = Rs. 48,000 ∴ R’s annual salary two years ago = 5x = 5 × 48,000 = Rs. 2,40,000 p.a. ∴ R’s annual salary one years ago = 2,40,000 × 150/100 = Rs. 3,60,000 p.a. ∴ R’s monthly salary one year ago = 360000/12 = Rs. 30,000 p.m.
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