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      Question

      The following questions each present two quantities,

      Quantity I and Quantity II. Compare the values of the two quantities and determine their relationship. Quantity I: The current age ratio of M to N is 2 : 3. N's age 3 years from now will be 17 years more than M’s age 3 years ago. Determine M’s present age. Quantity II: X’s current age is 1/3 of his father’s present age. His mother is currently 6 years younger than his father. If the average age of all three is 26, determine the age of X’s sister, who is 2 years younger than X.
      A Quantity I > Quantity II Correct Answer Incorrect Answer
      B Quantity I < Quantity II Correct Answer Incorrect Answer
      C Quantity I = Quantity II or No relation can be established Correct Answer Incorrect Answer
      D Quantity I ≥ Quantity II Correct Answer Incorrect Answer
      E Quantity I ≤ Quantity II Correct Answer Incorrect Answer

      Solution

      ATQ, Quantity I: Let the present age of M = 2x and present age of N = 3x According to the question, (3x+3)-(2x-3)=17 3x+3-2x+3=17 x=11 Present age of M = 22 years Quantity II: Let X's present age = x His father's age = 3x His mother's age = 3x-6 According to the question, X+3x+3x-6 = 26×3 7x = 78+6 = 84 x = 12 Present age of his sister = 10 years

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