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    Question

    The speed of train A is 180 km/hr and it can cross a

    pole in 4 seconds. Travelling in same direction Train A can cross a man sitting inside train B in 10 seconds. Quantity I: Speed of train B.(in m/s) Quantity II: If speed of train A is decreased by 20m/sec, then find the new speed of train A. (in m/s) Two quantities, Quantity I and Quantity II, are provided. Your task is to solve both quantities and determine the correct relationship between them. Choose the appropriate option.
    A Quantity-I > Quantity-II Correct Answer Incorrect Answer
    B Quantity I < Quantity II Correct Answer Incorrect Answer
    C Quantity I = Quantity II or No relation can be established Correct Answer Incorrect Answer
    D Quantity-I ≄ Quantity-II Correct Answer Incorrect Answer
    E Quantity-I ≀ Quantity-II Correct Answer Incorrect Answer

    Solution

    ATQ,

    Speed of Train A: 50 m/s. Length of Train A = 50×4 = 200m. Quantity I: Train A crosses a man in Train B in 10 seconds, so relative speed = 200/10 = 20m/s. Speed of Train B = 50 − 20 = 30m/s. Quantity II: New speed of Train A if decreased by 20 m/s = 50 − 20 = 30m/s. Hence, Quantity I = Quantity II or No relation can be established 

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