Question
In the question, two quantities I and II are given. You
have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II and choose the correct option. P + Q + R = 15, All the three values (P, Q and R) are not equal. Quantity I : What is the maximum value of product of three when all are positive integers. Quantity II : What is maximum value of product of three if value is greater than -10.Solution
Quantity I: For maximum product, we assume that the numbers are 4, 5 and 6. So, the product will be 120 Quantity II: Max. product, we assume that the numbers are -9, -8 and 32 So, the product will be = 72 × 32 Therefore, Quantity-I < Quantity-II
- Find the wrong number, in the given number series.
2, 4, 12, 48, 240, 1440 Find the wrong number in the given number series.
125, 129, 120, 136, 121, 147
120, 140, 178, 232, 300, 360
24, (24 + 2p), (24 + 4p), (24 + 6p), (24 + 8p), (24 + 10p)
120, 60, 80, 90, 180, 450
213, 215, 225, 257, 313, 393
Find the wrong number in the given number series.
134, 163, 194, 231, 274, 315
- In the given number series, find the wrong number.
3, 6, 12, 25, 48, 96, 192 Find the wrong number in the given number series.
1728, 121, 1000, 729, 512, 49
3960, 660, 720, 122, 180, 30