In the question, two Quantities I and II are given. You

Solution

ATQ, Let Anuj, Bhuvan and Charu be defined as A, B and C. Let the total work = 90 units (L.C.M of 11.25 and 3.6) Then, the efficiency of ‘B’ = 90 ÷ 11.25 = 8 units/day The combined efficiency of ‘A’ and ‘B’ = 90 ÷ 5 = 18 units/day So, the efficiency of ‘A’ = 18 – 8 = 10 units/day Number of days taken by ‘C’ alone to complete the entire work = 3.6 × 5 = 18 days Therefore, the efficiency of ‘C’ alone = 90 ÷ 18 = 5 units/day Quantity I: Work done by ‘A’ alone in 4 days = 10 × 4 = 40 units So, Quantity I = 40 units Quantity II: Work done by ‘B’ and ‘C’ together in 3 days = (8 + 5) × 3 = 39 units So, Quantity II = 39 units Therefore, Quantity I > Quantity II