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ATQ, 2p2 – 13p + 21 = 0 2p2 – 6p – 7p + 21 = 0 2p(p – 3) – 7(p – 3) = 0 p = + 3, + 7/2 p = + 3, + 3.5 q2 – 10q + 24 = 0 q2 – 6q – 4q + 24 = 0 q(q – 6) – 4(q – 6) = 0 q = + 6, + 4 Hence, p < q
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