Question
Six women and two men can
complete a task in 10 days. If the efficiency of a woman is twice that of a man, how many days will it take for eight women and five men to finish the same task?Solution
ATQ, Let the efficiency of each woman and each men be 'x' units/day and 'y' units/day Or, x = 2y Let the required number of days be 'd' days So, (6x + 2y) × 10 = (8x + 5y) × d Or, (12y + 2y) × 10 = (16y + 5y) × d Or, 14y × 10 = 21y × d So, d = (14y × 10)/21y = 20/3 = 6(2/3)
What value should come in place of (?) in the given expression.
450 ÷ 9 + 75% of 160 − 64 ÷ 4 = ?
2/5 of 3/4 of 7/9 of 14400 = ?
7/3 of 4/5 of 15/56 of ? = 83
[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
45% of 360 - 160 + ? = √324
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
18 × 15 + 86 – 58 =? + 38
√(24²+285-8²-172) = ?²
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