Question
Present average age of 4 friends: ‘A’, ‘B’,
‘C’ and ‘D’ is 40 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.Solution
Common difference between ages = (4/2) = 2 years. So, let present ages of ‘A’, ‘B’, ‘C’ and ‘D’ be ‘x’, (x + 2) years, (x + 4) years and (x + 6) years, respectively According to question: x + x + 2 + x + 4 + x + 6 = 160 Or, 4x = 148 Or, x = 37 years (Age of A) Present age of ‘C’ = x + 4 = 37 + 4 = 41 years Required sum = 37 + 41 = 78 years
Read the given statements and select which of the conclusions given in the options logically follows from the statements.
Statements:
A...
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No guitar is a violin.
Some violins are pianos.
All sitars are pianos.
Conclusions:
...Some clouds are not blues. Some rains are skies.
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Only a few Harpic is Lizol.
Only a few Lizol is Detergent.
No Harpic is Pesticide.
Conclusion :
I. Ev...
Two statements are given followed by two conclusions numbered I& II. Assuming the statements to be true, even if they seem to be at variance with commo...
Two statements are given followed by two conclusions numbered I & II. Assuming the statements to be true, even if they seem to be at variance with comm...
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Only Rain is Cloud
Some Star is Rainbow
A few Rainbow is Rain
Conclusions:
I. All Star can be Rain
... Statements: Some pins are mirrors.
All mirrors are boxes.
Conclusions:I. Some boxes are pins.
II. Some boxes are mirrors.
Statements:
No Summer is Winter.
Only a few Winter is Autumn
Some Summer are Spring.
Conclusions:
I. All W...
Three statements are given followed by three conclusions numbered I, II and III. Assuming the statements to be true, even if they seem to be at varianc...
