Question
A sum of ₹10,000 is invested in two schemes A and B.
Scheme A offers 10% per annum and scheme B offers 15% per annum. If the total interest earned after 2 years is ₹2,200, how much was invested in each scheme?Solution
Let amount invested in A = x and in B = 10000 - x. Interest from A after 2 years = (x × 10 × 2) / 100 = 0.2x. Interest from B after 2 years = [(10000 - x) × 15 × 2] / 100 = 3,000 - 0.3x. Total interest = 0.2x + (3000 - 0.3x) = 2200. 0.2x - 0.3x = 2200 - 3000 → -0.1x = -800 → x = 8000. Amount in A = 8000, Amount in B = 2000. Answer: a) ₹8,000 in A and ₹2,000 in B.
5.5 × 3.2 × 2.3 = ?
What value will come in place of (?) question mark in the given expression.
17 × 15 – 48 ÷ 4 + 9² = ?
Find the value of.
( ∛ ∛ 343 )3 × ( ∛ ∛216 )3
(3984 ÷ 24) x (5862 ÷ 40) = ?
5555 ÷ 11 ÷ 5 = 100 + ?
18 * 9 + 25% of 120 + 50% of 200 = ?
Simplify the following expressions and choose the correct option.
18² + (27 ÷ 3) × 11 − 250 = ?
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(20% of 820 – 56 + 11 × 8) 1/2 = ? – 62
Simplify the following expressions and choose the correct option.
√2116 + 152 ÷ 9 - 33
