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    Question

    A father is three times as old as his son. Four years

    ago, he was five times as old as his son. What are their present ages?
    A Father = 36, Son = 12 Correct Answer Incorrect Answer
    B Father = 45, Son = 15 Correct Answer Incorrect Answer
    C Father = 24, Son = 8 Correct Answer Incorrect Answer
    D Father = 30, Son = 10 Correct Answer Incorrect Answer

    Solution

    Let the son's present age be x years. Then the father's present age = 3x. Four years ago, their ages were: Father = 3x - 4, Son = x - 4. According to the problem: 3x - 4 = 5(x - 4) 3x - 4 = 5x - 20 20 - 4 = 5x - 3x 2x = 16 x = 8. Now calculate their present ages: Son = 8 years Father = 3 * 8 = 24 years Correct option: c) Father = 24, Son = 8

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