Question
A shopkeeper purchased two
packets of chips, A and B, for a combined cost of Rs. 2500. Packet A was sold with a 30% profit, while Packet B was sold with a 20% profit. If the overall profit percentage for the entire transaction was 26%, what is the cost price of Packet A?Solution
ATQ,
Let, cost price of Packet 'A' be Rs. x Cost price of Packet 'B' = Rs. (2500 – x) So, 1.3x + 1.2(2500 – x) = 1.26 × 2500 1.3x – 1.2x = 150 x = 150/0.1 = 1500 Cost price of Packet 'A' = Rs. 1500
More Quant Miscellaneous Questions
1(1/2)+ 11(1/3) + 111(1/2) + 1111(1/3) + 11111(1/2) = ?
18 × 15 + 86 – 58 =? + 38
2/5 of 3/4 of 7/9 of 7200 = ?
What value should come in place of the question mark (?) in the following question?
15 × 19 – 13 × 5 = 122 ...
18% of 200 - 16% of 150 = ?
If x²y² + (1/ (x2y2)) = 83, then the value of xy – 1/xy is:
56 × 18 + ? × 21 – 49 × 12 = 63 × 26
Solve for the ?
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
Relevant for Exams:
