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ATQ,
Let, cost price of Packet 'A' be Rs. x Cost price of Packet 'B' = Rs. (2500 – x) So, 1.3x + 1.2(2500 – x) = 1.26 × 2500 1.3x – 1.2x = 150 x = 150/0.1 = 1500 Cost price of Packet 'A' = Rs. 1500
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