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      Question

      A man observes the top of a tower at an angle of

      elevation of 45Β°. He walks 50 meters towards the tower, and the angle of elevation becomes 60Β°. What is the height of the tower?
      A 25(√3+3) meters Correct Answer Incorrect Answer
      B 50√3 meters Correct Answer Incorrect Answer
      C 25(√3-3) meters Correct Answer Incorrect Answer
      D 50(√3+3) meters Correct Answer Incorrect Answer

      Solution

      Let the height of the tower be h, and the initial distance from the man to the tower be d. From the first observation: tan(45°) = h/d, so h = d. From the second observation: tan(60°) = h/(d - 50), so h/(d - 50) = √3. Substitute h = d into the second equation and solve to get h = 25(√3+3) meters. Correct option: a) 25(√3+3) meters

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