Question
In the figure, ABCD is a cyclic quadrilateral with O as
center of the circle If ∠BOC = 136°, find ∠OBC.Solution
ATQ, In triangle OBC- ∠BOC+ ∠OBC+ ∠OCB = 180 136 + ∠OBC+ ∠OBC = 180 ( OB = OC ) 2 ∠OBC = 44 ∠OBC = 22
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