Question
l). 3p + 2q = 27 ll). 4p - 3q =
2 The given question presents two equations, labeled as I and II. You have to solve both equations and determine the relationship between them.Solution
ATQ, 3p+2q=27 --→ (1) 4p-3q=2 ----→ (2) By solving the equation (1) and (2), we get, p=5, q=6 Hence, p < q
More Quadratic equation Questions
(i) 2x² – 12x + 16 = 0
(ii) 2y² – 20y + 48 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
Solve: 3x² − 7x − 6 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs....
For what values of k does the equation x² – (k+1)x + k = 0 have two distinct real roots, both greater than 1?
I. x2 + x – 42 = 0
II. y2 + 6y – 27 = 0
I. 25p + 2(2p2 – 1) = 8(p + 5)
II. 8q2 + 35q – 78 = 0
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I. 2x² - 12x + 16 = 0  Â
II. 4y² - 8y - 12 = 0  Â
