Question
One of the roots of equation bp2 — (9b+3)p
+ 64 = 0 is 8, Determine the others root.Solution
ATQ, So, [9b + 3]/b = 8 + z [ z is another root] And, 8z = 64/b Or, z = 8/b So, [9b + 3]/b = 8+8/b Or, 9b + 3 = 8b + 8 Or, b = 5 So, z = 8/5
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